Base | Representation |
---|---|
bin | 101110111110110000… |
… | …111001101011001001 |
3 | 11211012121102010210111 |
4 | 232332300321223021 |
5 | 1311302423133231 |
6 | 35101342114321 |
7 | 3434035351066 |
oct | 567660715311 |
9 | 154177363714 |
10 | 50445130441 |
11 | 1a436a63152 |
12 | 9939b7b9a1 |
13 | 49ac053114 |
14 | 26278c1c6d |
15 | 14a39c04b1 |
hex | bbec39ac9 |
50445130441 has 2 divisors, whose sum is σ = 50445130442. Its totient is φ = 50445130440.
The previous prime is 50445130423. The next prime is 50445130457. The reversal of 50445130441 is 14403154405.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27754227216 + 22690903225 = 166596^2 + 150635^2 .
It is a cyclic number.
It is not a de Polignac number, because 50445130441 - 215 = 50445097673 is a prime.
It is a super-2 number, since 2×504451304412 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50445130471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25222565220 + 25222565221.
It is an arithmetic number, because the mean of its divisors is an integer number (25222565221).
Almost surely, 250445130441 is an apocalyptic number.
It is an amenable number.
50445130441 is a deficient number, since it is larger than the sum of its proper divisors (1).
50445130441 is an equidigital number, since it uses as much as digits as its factorization.
50445130441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 50445130441 its reverse (14403154405), we get a palindrome (64848284846).
The spelling of 50445130441 in words is "fifty billion, four hundred forty-five million, one hundred thirty thousand, four hundred forty-one".
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