Base | Representation |
---|---|
bin | 10110111100011000110001… |
… | …11111100001011010101011 |
3 | 20121122022001012111100222022 |
4 | 23132030120333201122223 |
5 | 23103112030413144433 |
6 | 255145545543415055 |
7 | 13425065201100014 |
oct | 1336143077413253 |
9 | 217568035440868 |
10 | 50453400131243 |
11 | 1509219206945a |
12 | 57aa25975448b |
13 | 221c9733717c5 |
14 | c65d5990000b |
15 | 5c761e67e698 |
hex | 2de318fe16ab |
50453400131243 has 2 divisors, whose sum is σ = 50453400131244. Its totient is φ = 50453400131242.
The previous prime is 50453400131219. The next prime is 50453400131293. The reversal of 50453400131243 is 34213100435405.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50453400131243 - 210 = 50453400130219 is a prime.
It is a super-4 number, since 4×504534001312434 (a number of 56 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (50453400131293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25226700065621 + 25226700065622.
It is an arithmetic number, because the mean of its divisors is an integer number (25226700065622).
Almost surely, 250453400131243 is an apocalyptic number.
50453400131243 is a deficient number, since it is larger than the sum of its proper divisors (1).
50453400131243 is an equidigital number, since it uses as much as digits as its factorization.
50453400131243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 50453400131243 its reverse (34213100435405), we get a palindrome (84666500566648).
The spelling of 50453400131243 in words is "fifty trillion, four hundred fifty-three billion, four hundred million, one hundred thirty-one thousand, two hundred forty-three".
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