Base | Representation |
---|---|
bin | 100100101111011110010… |
… | …0011001010110000110011 |
3 | 122212202021202100100001001 |
4 | 1021132330203022300303 |
5 | 1130213341434033111 |
6 | 14423453441422431 |
7 | 1030555340002216 |
oct | 111367443126063 |
9 | 18782252310031 |
10 | 5049749908531 |
11 | 16776501a4149 |
12 | 69681303aa17 |
13 | 2a826008ba73 |
14 | 1365a2bb577d |
15 | 8b5501651c1 |
hex | 497bc8cac33 |
5049749908531 has 2 divisors, whose sum is σ = 5049749908532. Its totient is φ = 5049749908530.
The previous prime is 5049749908493. The next prime is 5049749908537. The reversal of 5049749908531 is 1358099479405.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5049749908531 - 211 = 5049749906483 is a prime.
It is a super-2 number, since 2×50497499085312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5049749908537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2524874954265 + 2524874954266.
It is an arithmetic number, because the mean of its divisors is an integer number (2524874954266).
Almost surely, 25049749908531 is an apocalyptic number.
5049749908531 is a deficient number, since it is larger than the sum of its proper divisors (1).
5049749908531 is an equidigital number, since it uses as much as digits as its factorization.
5049749908531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48988800, while the sum is 64.
The spelling of 5049749908531 in words is "five trillion, forty-nine billion, seven hundred forty-nine million, nine hundred eight thousand, five hundred thirty-one".
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