Base | Representation |
---|---|
bin | 1110101100101001010… |
… | …11000110011001011001 |
3 | 1210021111200221110101011 |
4 | 13112110223012121121 |
5 | 31233222401444433 |
6 | 1023555112253521 |
7 | 51325335631651 |
oct | 7262453063131 |
9 | 1707450843334 |
10 | 505005499993 |
11 | 185198491755 |
12 | 81a593a12a1 |
13 | 38811183ba7 |
14 | 1a629d17361 |
15 | d20a2c43cd |
hex | 7594ac6659 |
505005499993 has 2 divisors, whose sum is σ = 505005499994. Its totient is φ = 505005499992.
The previous prime is 505005499981. The next prime is 505005500039. The reversal of 505005499993 is 399994500505.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 436270818064 + 68734681929 = 660508^2 + 262173^2 .
It is a cyclic number.
It is not a de Polignac number, because 505005499993 - 25 = 505005499961 is a prime.
It is not a weakly prime, because it can be changed into another prime (505005599993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252502749996 + 252502749997.
It is an arithmetic number, because the mean of its divisors is an integer number (252502749997).
Almost surely, 2505005499993 is an apocalyptic number.
It is an amenable number.
505005499993 is a deficient number, since it is larger than the sum of its proper divisors (1).
505005499993 is an equidigital number, since it uses as much as digits as its factorization.
505005499993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9841500, while the sum is 58.
The spelling of 505005499993 in words is "five hundred five billion, five million, four hundred ninety-nine thousand, nine hundred ninety-three".
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