Base | Representation |
---|---|
bin | 101111000011001110… |
… | …111001011000100001 |
3 | 11211101211111010000221 |
4 | 233003032321120201 |
5 | 1311431121234213 |
6 | 35113021043041 |
7 | 3435635533243 |
oct | 570316713041 |
9 | 154354433027 |
10 | 50520102433 |
11 | 1a47530a779 |
12 | 995b0b6481 |
13 | 49c1742a48 |
14 | 263383a093 |
15 | 14aa37e38d |
hex | bc33b9621 |
50520102433 has 2 divisors, whose sum is σ = 50520102434. Its totient is φ = 50520102432.
The previous prime is 50520102419. The next prime is 50520102449. The reversal of 50520102433 is 33420102505.
50520102433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50513461504 + 6640929 = 224752^2 + 2577^2 .
It is a cyclic number.
It is not a de Polignac number, because 50520102433 - 213 = 50520094241 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 50520102398 and 50520102407.
It is not a weakly prime, because it can be changed into another prime (50520102403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25260051216 + 25260051217.
It is an arithmetic number, because the mean of its divisors is an integer number (25260051217).
Almost surely, 250520102433 is an apocalyptic number.
It is an amenable number.
50520102433 is a deficient number, since it is larger than the sum of its proper divisors (1).
50520102433 is an equidigital number, since it uses as much as digits as its factorization.
50520102433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 25.
Adding to 50520102433 its reverse (33420102505), we get a palindrome (83940204938).
The spelling of 50520102433 in words is "fifty billion, five hundred twenty million, one hundred two thousand, four hundred thirty-three".
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