Base | Representation |
---|---|
bin | 111001011011110100100111… |
… | …0100000001100000010001011 |
3 | 2110020202202110002111122012002 |
4 | 1302313221032200030002023 |
5 | 1012204203413344020133 |
6 | 4550250111055141215 |
7 | 211261402133402531 |
oct | 16267511640140213 |
9 | 2406682402448162 |
10 | 505201140220043 |
11 | 136a776670a6743 |
12 | 487b344781480b |
13 | 188b835606a827 |
14 | 8ca7c194d2151 |
15 | 3d61693721ce8 |
hex | 1cb7a4e80c08b |
505201140220043 has 2 divisors, whose sum is σ = 505201140220044. Its totient is φ = 505201140220042.
The previous prime is 505201140220031. The next prime is 505201140220057. The reversal of 505201140220043 is 340022041102505.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-505201140220043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 505201140219988 and 505201140220015.
It is not a weakly prime, because it can be changed into another prime (505201140220003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252600570110021 + 252600570110022.
It is an arithmetic number, because the mean of its divisors is an integer number (252600570110022).
Almost surely, 2505201140220043 is an apocalyptic number.
505201140220043 is a deficient number, since it is larger than the sum of its proper divisors (1).
505201140220043 is an equidigital number, since it uses as much as digits as its factorization.
505201140220043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 29.
Adding to 505201140220043 its reverse (340022041102505), we get a palindrome (845223181322548).
The spelling of 505201140220043 in words is "five hundred five trillion, two hundred one billion, one hundred forty million, two hundred twenty thousand, forty-three".
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