Base | Representation |
---|---|
bin | 100100110000100111101… |
… | …0001100110110001111011 |
3 | 122212222122022100221210012 |
4 | 1021201033101212301323 |
5 | 1130233412124233301 |
6 | 14424542015212135 |
7 | 1031003340442334 |
oct | 111411721466173 |
9 | 18788568327705 |
10 | 5052211555451 |
11 | 16786a3791995 |
12 | 69719b51704b |
13 | 2a8563080188 |
14 | 136757ac128b |
15 | 8b646316ebb |
hex | 4984f466c7b |
5052211555451 has 2 divisors, whose sum is σ = 5052211555452. Its totient is φ = 5052211555450.
The previous prime is 5052211555429. The next prime is 5052211555483. The reversal of 5052211555451 is 1545551122505.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5052211555451 is a prime.
It is a super-2 number, since 2×50522115554512 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5052211555399 and 5052211555408.
It is not a weakly prime, because it can be changed into another prime (5052231555451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2526105777725 + 2526105777726.
It is an arithmetic number, because the mean of its divisors is an integer number (2526105777726).
Almost surely, 25052211555451 is an apocalyptic number.
5052211555451 is a deficient number, since it is larger than the sum of its proper divisors (1).
5052211555451 is an equidigital number, since it uses as much as digits as its factorization.
5052211555451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 250000, while the sum is 41.
Adding to 5052211555451 its reverse (1545551122505), we get a palindrome (6597762677956).
The spelling of 5052211555451 in words is "five trillion, fifty-two billion, two hundred eleven million, five hundred fifty-five thousand, four hundred fifty-one".
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