Base | Representation |
---|---|
bin | 1001011010011000… |
… | …11111101010011001 |
3 | 111001011112001011020 |
4 | 10231030133222121 |
5 | 40322110424213 |
6 | 2153231553053 |
7 | 236136432225 |
oct | 45514375231 |
9 | 14034461136 |
10 | 5053217433 |
11 | 2163456060 |
12 | b9038b789 |
13 | 626ba25b4 |
14 | 35d195785 |
15 | 1e8969923 |
hex | 12d31fa99 |
5053217433 has 32 divisors (see below), whose sum is σ = 7628031360. Its totient is φ = 2947445760.
The previous prime is 5053217423. The next prime is 5053217443. The reversal of 5053217433 is 3347123505.
It is an interprime number because it is at equal distance from previous prime (5053217423) and next prime (5053217443).
It is not a de Polignac number, because 5053217433 - 25 = 5053217401 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 5053217394 and 5053217403.
It is not an unprimeable number, because it can be changed into a prime (5053217423) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 295041 + ... + 311697.
It is an arithmetic number, because the mean of its divisors is an integer number (238375980).
Almost surely, 25053217433 is an apocalyptic number.
It is an amenable number.
5053217433 is a deficient number, since it is larger than the sum of its proper divisors (2574813927).
5053217433 is a wasteful number, since it uses less digits than its factorization.
5053217433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17017.
The product of its (nonzero) digits is 37800, while the sum is 33.
The square root of 5053217433 is about 71085.9861927792. The cubic root of 5053217433 is about 1716.0212514552.
The spelling of 5053217433 in words is "five billion, fifty-three million, two hundred seventeen thousand, four hundred thirty-three".
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