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5053241240273 is a prime number
BaseRepresentation
bin100100110001000110010…
…1001100010101011010001
3122220002022001220100211002
41021202030221202223101
51130243014224142043
614425232121031345
71031041012560032
oct111421451425321
918802261810732
105053241240273
111679081a40386
12697428325555
132a86984b1a35
14136814758a89
158b6a690dbb8
hex4988ca62ad1

5053241240273 has 2 divisors, whose sum is σ = 5053241240274. Its totient is φ = 5053241240272.

The previous prime is 5053241240129. The next prime is 5053241240323. The reversal of 5053241240273 is 3720421423505.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4570116155089 + 483125085184 = 2137783^2 + 695072^2 .

It is a cyclic number.

It is not a de Polignac number, because 5053241240273 - 238 = 4778363333329 is a prime.

It is a super-3 number, since 3×50532412402733 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (5053241230273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2526620620136 + 2526620620137.

It is an arithmetic number, because the mean of its divisors is an integer number (2526620620137).

Almost surely, 25053241240273 is an apocalyptic number.

It is an amenable number.

5053241240273 is a deficient number, since it is larger than the sum of its proper divisors (1).

5053241240273 is an equidigital number, since it uses as much as digits as its factorization.

5053241240273 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 201600, while the sum is 38.

Adding to 5053241240273 its reverse (3720421423505), we get a palindrome (8773662663778).

The spelling of 5053241240273 in words is "five trillion, fifty-three billion, two hundred forty-one million, two hundred forty thousand, two hundred seventy-three".