Base | Representation |
---|---|
bin | 100100110001001000010… |
… | …1111110110100011111010 |
3 | 122220002110212021220011102 |
4 | 1021202100233312203322 |
5 | 1130243134330102300 |
6 | 14425243014531402 |
7 | 1031042506212542 |
oct | 111422057664372 |
9 | 18802425256142 |
10 | 5053310003450 |
11 | 1679107837155 |
12 | 697447366b62 |
13 | 2a86a98095c7 |
14 | 13681d938322 |
15 | 8b6ac9930d5 |
hex | 49890bf68fa |
5053310003450 has 12 divisors (see below), whose sum is σ = 9399156606510. Its totient is φ = 2021324001360.
The previous prime is 5053310003437. The next prime is 5053310003453. The reversal of 5053310003450 is 543000133505.
It can be written as a sum of positive squares in 3 ways, for example, as 4109227657129 + 944082346321 = 2027123^2 + 971639^2 .
It is a super-3 number, since 3×50533100034503 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (5053310003453) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 50533099985 + ... + 50533100084.
Almost surely, 25053310003450 is an apocalyptic number.
5053310003450 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
5053310003450 is a deficient number, since it is larger than the sum of its proper divisors (4345846603060).
5053310003450 is a wasteful number, since it uses less digits than its factorization.
5053310003450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101066200081 (or 101066200076 counting only the distinct ones).
The product of its (nonzero) digits is 13500, while the sum is 29.
Adding to 5053310003450 its reverse (543000133505), we get a palindrome (5596310136955).
The spelling of 5053310003450 in words is "five trillion, fifty-three billion, three hundred ten million, three thousand, four hundred fifty".
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