Base | Representation |
---|---|
bin | 1110101101010100000… |
… | …10110000000001010011 |
3 | 1210022102200120020012020 |
4 | 13112222002300001103 |
5 | 31234441142140311 |
6 | 1024054440502523 |
7 | 51340251206451 |
oct | 7265202600123 |
9 | 1708380506166 |
10 | 505364021331 |
11 | 1853618a7084 |
12 | 81b3947aa43 |
13 | 3886a5318b0 |
14 | 1a6617a19d1 |
15 | d22b9e2c06 |
hex | 75aa0b0053 |
505364021331 has 48 divisors (see below), whose sum is σ = 749973772800. Its totient is φ = 300891894912.
The previous prime is 505364021321. The next prime is 505364021363. The reversal of 505364021331 is 133120463505.
It is not a de Polignac number, because 505364021331 - 214 = 505364004947 is a prime.
It is a super-2 number, since 2×5053640213312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 505364021292 and 505364021301.
It is not an unprimeable number, because it can be changed into a prime (505364021311) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 9530550 + ... + 9583428.
It is an arithmetic number, because the mean of its divisors is an integer number (15624453600).
Almost surely, 2505364021331 is an apocalyptic number.
505364021331 is a deficient number, since it is larger than the sum of its proper divisors (244609751469).
505364021331 is a wasteful number, since it uses less digits than its factorization.
505364021331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53148 (or 53111 counting only the distinct ones).
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 505364021331 its reverse (133120463505), we get a palindrome (638484484836).
The spelling of 505364021331 in words is "five hundred five billion, three hundred sixty-four million, twenty-one thousand, three hundred thirty-one".
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