Base | Representation |
---|---|
bin | 1110101101011001000… |
… | …00110000010100100001 |
3 | 1210022112120111120201122 |
4 | 13112230200300110201 |
5 | 31240032243110223 |
6 | 1024102520342025 |
7 | 51341263240433 |
oct | 7265440602441 |
9 | 1708476446648 |
10 | 505405441313 |
11 | 185383217573 |
12 | 81b4b314915 |
13 | 38875ca4866 |
14 | 1a6670a4653 |
15 | d2304755c8 |
hex | 75ac830521 |
505405441313 has 2 divisors, whose sum is σ = 505405441314. Its totient is φ = 505405441312.
The previous prime is 505405441309. The next prime is 505405441327. The reversal of 505405441313 is 313144504505.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 503770613824 + 1634827489 = 709768^2 + 40433^2 .
It is a cyclic number.
It is not a de Polignac number, because 505405441313 - 22 = 505405441309 is a prime.
It is not a weakly prime, because it can be changed into another prime (505405441393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252702720656 + 252702720657.
It is an arithmetic number, because the mean of its divisors is an integer number (252702720657).
Almost surely, 2505405441313 is an apocalyptic number.
It is an amenable number.
505405441313 is a deficient number, since it is larger than the sum of its proper divisors (1).
505405441313 is an equidigital number, since it uses as much as digits as its factorization.
505405441313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 505405441313 its reverse (313144504505), we get a palindrome (818549945818).
The spelling of 505405441313 in words is "five hundred five billion, four hundred five million, four hundred forty-one thousand, three hundred thirteen".
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