Base | Representation |
---|---|
bin | 100100110001100010111… |
… | …1100001111111001111001 |
3 | 122220011210001120122102012 |
4 | 1021203011330033321321 |
5 | 1130302001311223213 |
6 | 14425511335015305 |
7 | 1031103563642321 |
oct | 111430574177171 |
9 | 18804701518365 |
10 | 5054202445433 |
11 | 1679525577009 |
12 | 69765620a535 |
13 | 2a87bc687a9b |
14 | 1368a6288281 |
15 | 8b710eca4a8 |
hex | 498c5f0fe79 |
5054202445433 has 2 divisors, whose sum is σ = 5054202445434. Its totient is φ = 5054202445432.
The previous prime is 5054202445337. The next prime is 5054202445447. The reversal of 5054202445433 is 3345442024505.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4784578767424 + 269623678009 = 2187368^2 + 519253^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5054202445433 is a prime.
It is not a weakly prime, because it can be changed into another prime (5054202445333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527101222716 + 2527101222717.
It is an arithmetic number, because the mean of its divisors is an integer number (2527101222717).
Almost surely, 25054202445433 is an apocalyptic number.
It is an amenable number.
5054202445433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5054202445433 is an equidigital number, since it uses as much as digits as its factorization.
5054202445433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152000, while the sum is 41.
Adding to 5054202445433 its reverse (3345442024505), we get a palindrome (8399644469938).
The spelling of 5054202445433 in words is "five trillion, fifty-four billion, two hundred two million, four hundred forty-five thousand, four hundred thirty-three".
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