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5054204131033 = 42382311925271
BaseRepresentation
bin100100110001100011000…
…0010101011011011011001
3122220011210011202021121211
41021203012002223123121
51130302002224143113
614425511435103121
71031103614162521
oct111430602533331
918804704667554
105054204131033
111679526518472
126976568a1aa1
132a87bcb28095
141368a65a6681
158b71120eb3d
hex498c60ab6d9

5054204131033 has 4 divisors (see below), whose sum is σ = 5054216480128. Its totient is φ = 5054191781940.

The previous prime is 5054204130973. The next prime is 5054204131037. The reversal of 5054204131033 is 3301314024505.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5054204131033 - 217 = 5054203999961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5054204130986 and 5054204131004.

It is not an unprimeable number, because it can be changed into a prime (5054204131037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5538813 + ... + 6386458.

It is an arithmetic number, because the mean of its divisors is an integer number (1263554120032).

Almost surely, 25054204131033 is an apocalyptic number.

It is an amenable number.

5054204131033 is a deficient number, since it is larger than the sum of its proper divisors (12349095).

5054204131033 is a wasteful number, since it uses less digits than its factorization.

5054204131033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12349094.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 5054204131033 its reverse (3301314024505), we get a palindrome (8355518155538).

The spelling of 5054204131033 in words is "five trillion, fifty-four billion, two hundred four million, one hundred thirty-one thousand, thirty-three".

Divisors: 1 423823 11925271 5054204131033