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5055005484121 is a prime number
BaseRepresentation
bin100100110001111010111…
…0011100110010001011001
3122220020212000122020101211
41021203311303212101121
51130310122400442441
614430123142543121
71031132514443065
oct111436563462131
918806760566354
105055005484121
1116798a78a294a
1269783b137aa1
132a88b9b62ac8
14136940ba4aa5
158b75b752a81
hex498f5ce6459

5055005484121 has 2 divisors, whose sum is σ = 5055005484122. Its totient is φ = 5055005484120.

The previous prime is 5055005484101. The next prime is 5055005484163. The reversal of 5055005484121 is 1214845005505.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4166350474896 + 888655009225 = 2041164^2 + 942685^2 .

It is a cyclic number.

It is not a de Polignac number, because 5055005484121 - 213 = 5055005475929 is a prime.

It is a super-3 number, since 3×50550054841213 (a number of 39 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (5055005484101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527502742060 + 2527502742061.

It is an arithmetic number, because the mean of its divisors is an integer number (2527502742061).

Almost surely, 25055005484121 is an apocalyptic number.

It is an amenable number.

5055005484121 is a deficient number, since it is larger than the sum of its proper divisors (1).

5055005484121 is an equidigital number, since it uses as much as digits as its factorization.

5055005484121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 160000, while the sum is 40.

The spelling of 5055005484121 in words is "five trillion, fifty-five billion, five million, four hundred eighty-four thousand, one hundred twenty-one".