Base | Representation |
---|---|
bin | 10110111111001101110101… |
… | …00111111111000000110001 |
3 | 20121222120221022100202111001 |
4 | 23133212322213333000301 |
5 | 23111210112343304023 |
6 | 255302343042522001 |
7 | 13435106010113602 |
oct | 1337467247770061 |
9 | 217876838322431 |
10 | 50550601150513 |
11 | 1511a431552942 |
12 | 5805066066301 |
13 | 2228b9401cc19 |
14 | c6a93ad23da9 |
15 | 5c9e0ccd16ad |
hex | 2df9ba9ff031 |
50550601150513 has 2 divisors, whose sum is σ = 50550601150514. Its totient is φ = 50550601150512.
The previous prime is 50550601150433. The next prime is 50550601150519. The reversal of 50550601150513 is 31505110605505.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47286967408704 + 3263633741809 = 6876552^2 + 1806553^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50550601150513 is a prime.
It is not a weakly prime, because it can be changed into another prime (50550601150519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25275300575256 + 25275300575257.
It is an arithmetic number, because the mean of its divisors is an integer number (25275300575257).
Almost surely, 250550601150513 is an apocalyptic number.
It is an amenable number.
50550601150513 is a deficient number, since it is larger than the sum of its proper divisors (1).
50550601150513 is an equidigital number, since it uses as much as digits as its factorization.
50550601150513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56250, while the sum is 37.
The spelling of 50550601150513 in words is "fifty trillion, five hundred fifty billion, six hundred one million, one hundred fifty thousand, five hundred thirteen".
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