Base | Representation |
---|---|
bin | 10110111111010110001110… |
… | …11010001100010011100011 |
3 | 20122000000120120200211112211 |
4 | 23133223013122030103203 |
5 | 23111243331303343201 |
6 | 255304410332102551 |
7 | 13435325524625362 |
oct | 1337530732142343 |
9 | 218000516624484 |
10 | 50555110606051 |
11 | 15121335a715a7 |
12 | 5805b04304a57 |
13 | 22294323574cc |
14 | c6ac47bb17d9 |
15 | 5ca0c3b3b651 |
hex | 2dfac768c4e3 |
50555110606051 has 4 divisors (see below), whose sum is σ = 50556059748072. Its totient is φ = 50554161464032.
The previous prime is 50555110606043. The next prime is 50555110606069. The reversal of 50555110606051 is 15060601155505.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50555110606051 - 23 = 50555110606043 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 50555110605995 and 50555110606013.
It is not an unprimeable number, because it can be changed into a prime (50555110606031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 474491110 + ... + 474597643.
It is an arithmetic number, because the mean of its divisors is an integer number (12639014937018).
Almost surely, 250555110606051 is an apocalyptic number.
50555110606051 is a deficient number, since it is larger than the sum of its proper divisors (949142021).
50555110606051 is an equidigital number, since it uses as much as digits as its factorization.
50555110606051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 949142020.
The product of its (nonzero) digits is 112500, while the sum is 40.
The spelling of 50555110606051 in words is "fifty trillion, five hundred fifty-five billion, one hundred ten million, six hundred six thousand, fifty-one".
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