Base | Representation |
---|---|
bin | 101111000101100111… |
… | …010010010100010011 |
3 | 11211111121122200102011 |
4 | 233011213102110103 |
5 | 1312021333103301 |
6 | 35121005203351 |
7 | 3436632223621 |
oct | 570547222423 |
9 | 154447580364 |
10 | 50560050451 |
11 | 1a495915269 |
12 | 9970560557 |
13 | 49c9abba21 |
14 | 2638c78511 |
15 | 14adb20a51 |
hex | bc59d2513 |
50560050451 has 2 divisors, whose sum is σ = 50560050452. Its totient is φ = 50560050450.
The previous prime is 50560050427. The next prime is 50560050503. The reversal of 50560050451 is 15405006505.
50560050451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50560050451 - 25 = 50560050419 is a prime.
It is not a weakly prime, because it can be changed into another prime (50560057451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25280025225 + 25280025226.
It is an arithmetic number, because the mean of its divisors is an integer number (25280025226).
Almost surely, 250560050451 is an apocalyptic number.
50560050451 is a deficient number, since it is larger than the sum of its proper divisors (1).
50560050451 is an equidigital number, since it uses as much as digits as its factorization.
50560050451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15000, while the sum is 31.
Adding to 50560050451 its reverse (15405006505), we get a palindrome (65965056956).
The spelling of 50560050451 in words is "fifty billion, five hundred sixty million, fifty thousand, four hundred fifty-one".
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