Base | Representation |
---|---|
bin | 1110101110100001000… |
… | …11000000010111101001 |
3 | 1210101002201002220120201 |
4 | 13113100203000113221 |
5 | 31242302030323423 |
6 | 1024242514352201 |
7 | 51362254061545 |
oct | 7272043002751 |
9 | 1711081086521 |
10 | 506010011113 |
11 | 185663506832 |
12 | 8209988b661 |
13 | 38941310479 |
14 | 1a6c34baa25 |
15 | d2685972ad |
hex | 75d08c05e9 |
506010011113 has 2 divisors, whose sum is σ = 506010011114. Its totient is φ = 506010011112.
The previous prime is 506010011081. The next prime is 506010011159. The reversal of 506010011113 is 311110010605.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 491754367504 + 14255643609 = 701252^2 + 119397^2 .
It is a cyclic number.
It is not a de Polignac number, because 506010011113 - 25 = 506010011081 is a prime.
It is a super-2 number, since 2×5060100111132 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (506010011513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 253005005556 + 253005005557.
It is an arithmetic number, because the mean of its divisors is an integer number (253005005557).
Almost surely, 2506010011113 is an apocalyptic number.
It is an amenable number.
506010011113 is a deficient number, since it is larger than the sum of its proper divisors (1).
506010011113 is an equidigital number, since it uses as much as digits as its factorization.
506010011113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 19.
Adding to 506010011113 its reverse (311110010605), we get a palindrome (817120021718).
The spelling of 506010011113 in words is "five hundred six billion, ten million, eleven thousand, one hundred thirteen".
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