Base | Representation |
---|---|
bin | 1110101111010001001… |
… | …00101101111110010001 |
3 | 1210102010210121121201212 |
4 | 13113220210231332101 |
5 | 31244113224110413 |
6 | 1024350514305505 |
7 | 51405250303436 |
oct | 7275044557621 |
9 | 1712123547655 |
10 | 506413113233 |
11 | 185850000385 |
12 | 82190888295 |
13 | 389a6999a31 |
14 | 1a720c4bb8d |
15 | d28db6eca8 |
hex | 75e892df91 |
506413113233 has 2 divisors, whose sum is σ = 506413113234. Its totient is φ = 506413113232.
The previous prime is 506413113223. The next prime is 506413113247. The reversal of 506413113233 is 332311314605.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 502656894289 + 3756218944 = 708983^2 + 61288^2 .
It is a cyclic number.
It is not a de Polignac number, because 506413113233 - 210 = 506413112209 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 506413113233.
It is not a weakly prime, because it can be changed into another prime (506413113223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 253206556616 + 253206556617.
It is an arithmetic number, because the mean of its divisors is an integer number (253206556617).
Almost surely, 2506413113233 is an apocalyptic number.
It is an amenable number.
506413113233 is a deficient number, since it is larger than the sum of its proper divisors (1).
506413113233 is an equidigital number, since it uses as much as digits as its factorization.
506413113233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 32.
Adding to 506413113233 its reverse (332311314605), we get a palindrome (838724427838).
The spelling of 506413113233 in words is "five hundred six billion, four hundred thirteen million, one hundred thirteen thousand, two hundred thirty-three".
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