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50651300041 = 618310004207
BaseRepresentation
bin101111001011000011…
…011000000011001001
311211201222100122022121
4233023003120003021
51312213213100131
635134025051241
73442120642456
oct571303300311
9154658318277
1050651300041
111a53237a451
129997026b21
134a1298a674
14264702c82d
1514b6b47911
hexbcb0d80c9

50651300041 has 8 divisors (see below), whose sum is σ = 52101915264. Its totient is φ = 49220693520.

The previous prime is 50651300033. The next prime is 50651300053. The reversal of 50651300041 is 14000315605.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 50651300041 - 23 = 50651300033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 50651299979 and 50651300015.

It is not an unprimeable number, because it can be changed into a prime (50651309041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4997041 + ... + 5007166.

It is an arithmetic number, because the mean of its divisors is an integer number (6512739408).

Almost surely, 250651300041 is an apocalyptic number.

It is an amenable number.

50651300041 is a deficient number, since it is larger than the sum of its proper divisors (1450615223).

50651300041 is a wasteful number, since it uses less digits than its factorization.

50651300041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10004351.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 50651300041 its reverse (14000315605), we get a palindrome (64651615646).

The spelling of 50651300041 in words is "fifty billion, six hundred fifty-one million, three hundred thousand, forty-one".

Divisors: 1 61 83 5063 10004207 610256627 830349181 50651300041