Base | Representation |
---|---|
bin | 101111001101111001… |
… | …010101100101011001 |
3 | 11211212022010001120102 |
4 | 233031321111211121 |
5 | 1312312421001103 |
6 | 35142451305145 |
7 | 3443240251034 |
oct | 571571254531 |
9 | 154768101512 |
10 | 50699000153 |
11 | 1a55729a22a |
12 | 99aabab1b5 |
13 | 4a1c81bc99 |
14 | 264d4c801b |
15 | 14bae1ae88 |
hex | bcde55959 |
50699000153 has 2 divisors, whose sum is σ = 50699000154. Its totient is φ = 50699000152.
The previous prime is 50699000087. The next prime is 50699000173. The reversal of 50699000153 is 35100099605.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38945838409 + 11753161744 = 197347^2 + 108412^2 .
It is a cyclic number.
It is not a de Polignac number, because 50699000153 - 228 = 50430564697 is a prime.
It is not a weakly prime, because it can be changed into another prime (50699000173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25349500076 + 25349500077.
It is an arithmetic number, because the mean of its divisors is an integer number (25349500077).
Almost surely, 250699000153 is an apocalyptic number.
It is an amenable number.
50699000153 is a deficient number, since it is larger than the sum of its proper divisors (1).
50699000153 is an equidigital number, since it uses as much as digits as its factorization.
50699000153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36450, while the sum is 38.
Adding to 50699000153 its reverse (35100099605), we get a palindrome (85799099758).
The spelling of 50699000153 in words is "fifty billion, six hundred ninety-nine million, one hundred fifty-three", and thus it is an aban number.
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