Base | Representation |
---|---|
bin | 100100111000111101001… |
… | …0000010110011111100011 |
3 | 122221200211212011222022112 |
4 | 1021301322100112133203 |
5 | 1131032042301003232 |
6 | 14441102203025535 |
7 | 1032206054213024 |
oct | 111617220263743 |
9 | 18850755158275 |
10 | 5070112516067 |
11 | 168524a379615 |
12 | 69a75650b2ab |
13 | 2aa156915271 |
14 | 1375752cac4b |
15 | 8bd42b5a4b2 |
hex | 49c7a4167e3 |
5070112516067 has 2 divisors, whose sum is σ = 5070112516068. Its totient is φ = 5070112516066.
The previous prime is 5070112516031. The next prime is 5070112516151. The reversal of 5070112516067 is 7606152110705.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5070112516067 - 216 = 5070112450531 is a prime.
It is a super-3 number, since 3×50701125160673 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (2070112516067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2535056258033 + 2535056258034.
It is an arithmetic number, because the mean of its divisors is an integer number (2535056258034).
Almost surely, 25070112516067 is an apocalyptic number.
5070112516067 is a deficient number, since it is larger than the sum of its proper divisors (1).
5070112516067 is an equidigital number, since it uses as much as digits as its factorization.
5070112516067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 88200, while the sum is 41.
The spelling of 5070112516067 in words is "five trillion, seventy billion, one hundred twelve million, five hundred sixteen thousand, sixty-seven".
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