Base | Representation |
---|---|
bin | 100100111001011111110… |
… | …0111100010001101111011 |
3 | 122221210211221220022210121 |
4 | 1021302333213202031323 |
5 | 1131041433203040212 |
6 | 14441413453154111 |
7 | 1032246644434462 |
oct | 111627747421573 |
9 | 18853757808717 |
10 | 5071276221307 |
11 | 168579724558a |
12 | 69aa2018b937 |
13 | 2aa2b0a3c54a |
14 | 137645a8d9d9 |
15 | 8bdaedc6d07 |
hex | 49cbf9e237b |
5071276221307 has 8 divisors (see below), whose sum is σ = 5125384060160. Its totient is φ = 5017262077800.
The previous prime is 5071276221289. The next prime is 5071276221379. The reversal of 5071276221307 is 7031226721705.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5071276221307 - 211 = 5071276219259 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5071276221397) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23315007 + ... + 23531512.
It is an arithmetic number, because the mean of its divisors is an integer number (640673007520).
Almost surely, 25071276221307 is an apocalyptic number.
5071276221307 is a deficient number, since it is larger than the sum of its proper divisors (54107838853).
5071276221307 is a wasteful number, since it uses less digits than its factorization.
5071276221307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46847673.
The product of its (nonzero) digits is 246960, while the sum is 43.
The spelling of 5071276221307 in words is "five trillion, seventy-one billion, two hundred seventy-six million, two hundred twenty-one thousand, three hundred seven".
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