Base | Representation |
---|---|
bin | 101111010010010100… |
… | …011011000101101011 |
3 | 11212001110202021120221 |
4 | 233102110123011223 |
5 | 1312440420200301 |
6 | 35154102030511 |
7 | 3445131105466 |
oct | 572224330553 |
9 | 155043667527 |
10 | 50773209451 |
11 | 1a595175828 |
12 | 9a0ba18437 |
13 | 4a32002703 |
14 | 26592c42dd |
15 | 14c26c8da1 |
hex | bd251b16b |
50773209451 has 2 divisors, whose sum is σ = 50773209452. Its totient is φ = 50773209450.
The previous prime is 50773209427. The next prime is 50773209463. The reversal of 50773209451 is 15490237705.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50773209451 - 229 = 50236338539 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 50773209398 and 50773209407.
It is not a weakly prime, because it can be changed into another prime (50773200451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25386604725 + 25386604726.
It is an arithmetic number, because the mean of its divisors is an integer number (25386604726).
Almost surely, 250773209451 is an apocalyptic number.
50773209451 is a deficient number, since it is larger than the sum of its proper divisors (1).
50773209451 is an equidigital number, since it uses as much as digits as its factorization.
50773209451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 264600, while the sum is 43.
The spelling of 50773209451 in words is "fifty billion, seven hundred seventy-three million, two hundred nine thousand, four hundred fifty-one".
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