Base | Representation |
---|---|
bin | 101111011000100000… |
… | …011101111011110011 |
3 | 11212022201002220210022 |
4 | 233120200131323303 |
5 | 1313144004431011 |
6 | 35212251154055 |
7 | 3450531422624 |
oct | 573040357363 |
9 | 155281086708 |
10 | 50877030131 |
11 | 1a638836844 |
12 | 9a3a74592b |
13 | 4a4a683275 |
14 | 2668dcba4b |
15 | 14cb8858db |
hex | bd881def3 |
50877030131 has 2 divisors, whose sum is σ = 50877030132. Its totient is φ = 50877030130.
The previous prime is 50877030077. The next prime is 50877030163. The reversal of 50877030131 is 13103077805.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50877030131 - 230 = 49803288307 is a prime.
It is a super-3 number, since 3×508770301313 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 50877030091 and 50877030100.
It is not a weakly prime, because it can be changed into another prime (50877030731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25438515065 + 25438515066.
It is an arithmetic number, because the mean of its divisors is an integer number (25438515066).
Almost surely, 250877030131 is an apocalyptic number.
50877030131 is a deficient number, since it is larger than the sum of its proper divisors (1).
50877030131 is an equidigital number, since it uses as much as digits as its factorization.
50877030131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17640, while the sum is 35.
The spelling of 50877030131 in words is "fifty billion, eight hundred seventy-seven million, thirty thousand, one hundred thirty-one".
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