Base | Representation |
---|---|
bin | 1001011111100000… |
… | …01011101010011011 |
3 | 111011011021002012022 |
4 | 10233300023222123 |
5 | 40414102032011 |
6 | 2201403405055 |
7 | 240200236334 |
oct | 45760135233 |
9 | 14134232168 |
10 | 5096127131 |
11 | 21856a3817 |
12 | ba282378b |
13 | 632a47654 |
14 | 364b6528b |
15 | 1ec5e38db |
hex | 12fc0ba9b |
5096127131 has 2 divisors, whose sum is σ = 5096127132. Its totient is φ = 5096127130.
The previous prime is 5096127019. The next prime is 5096127137. The reversal of 5096127131 is 1317216905.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5096127131 - 210 = 5096126107 is a prime.
It is a super-2 number, since 2×50961271312 = 51941023470628582322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5096127091 and 5096127100.
It is not a weakly prime, because it can be changed into another prime (5096127137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2548063565 + 2548063566.
It is an arithmetic number, because the mean of its divisors is an integer number (2548063566).
Almost surely, 25096127131 is an apocalyptic number.
5096127131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5096127131 is an equidigital number, since it uses as much as digits as its factorization.
5096127131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340, while the sum is 35.
The square root of 5096127131 is about 71387.1636290447. The cubic root of 5096127131 is about 1720.8647998129.
The spelling of 5096127131 in words is "five billion, ninety-six million, one hundred twenty-seven thousand, one hundred thirty-one".
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