Base | Representation |
---|---|
bin | 1100001001110… |
… | …0000000010011 |
3 | 10112220120120121 |
4 | 3002130000103 |
5 | 101022030033 |
6 | 5020251111 |
7 | 1156146313 |
oct | 302340023 |
9 | 115816517 |
10 | 50970643 |
11 | 26853aa9 |
12 | 150a0a97 |
13 | a738159 |
14 | 6aab443 |
15 | 471c62d |
hex | 309c013 |
50970643 has 2 divisors, whose sum is σ = 50970644. Its totient is φ = 50970642.
The previous prime is 50970617. The next prime is 50970649. The reversal of 50970643 is 34607905.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50970643 - 25 = 50970611 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 50970599 and 50970608.
It is not a weakly prime, because it can be changed into another prime (50970649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25485321 + 25485322.
It is an arithmetic number, because the mean of its divisors is an integer number (25485322).
Almost surely, 250970643 is an apocalyptic number.
50970643 is a deficient number, since it is larger than the sum of its proper divisors (1).
50970643 is an equidigital number, since it uses as much as digits as its factorization.
50970643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 22680, while the sum is 34.
The square root of 50970643 is about 7139.3727315500. The cubic root of 50970643 is about 370.7718074700.
The spelling of 50970643 in words is "fifty million, nine hundred seventy thousand, six hundred forty-three".
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