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51000110033 is a prime number
BaseRepresentation
bin101111011111110101…
…111110101111010001
311212122021201000200012
4233133311332233101
51313422012010113
635232405204305
73453554532305
oct573765765721
9155567630605
1051000110033
111a6a1261574
129a73a00695
134a6a018002
14267b4a9d05
1514d7598aa8
hexbdfd7ebd1

51000110033 has 2 divisors, whose sum is σ = 51000110034. Its totient is φ = 51000110032.

The previous prime is 51000109999. The next prime is 51000110129. The reversal of 51000110033 is 33001100015.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49451530129 + 1548579904 = 222377^2 + 39352^2 .

It is a cyclic number.

It is not a de Polignac number, because 51000110033 - 26 = 51000109969 is a prime.

It is a super-2 number, since 2×510001100332 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (51000110333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25500055016 + 25500055017.

It is an arithmetic number, because the mean of its divisors is an integer number (25500055017).

Almost surely, 251000110033 is an apocalyptic number.

It is an amenable number.

51000110033 is a deficient number, since it is larger than the sum of its proper divisors (1).

51000110033 is an equidigital number, since it uses as much as digits as its factorization.

51000110033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45, while the sum is 14.

Adding to 51000110033 its reverse (33001100015), we get a palindrome (84001210048).

The spelling of 51000110033 in words is "fifty-one billion, one hundred ten thousand, thirty-three".