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51000125131 = 411498348359
BaseRepresentation
bin101111011111110110…
…000010011011001011
311212122021201210101101
4233133312002123023
51313422013001011
635232405402231
73453554624314
oct573766023313
9155567653341
1051000125131
111a6a127194a
129a73a09377
134a6a021b47
14267b4b160b
1514d759d2c1
hexbdfd826cb

51000125131 has 8 divisors (see below), whose sum is σ = 52594668000. Its totient is φ = 49422279360.

The previous prime is 51000125093. The next prime is 51000125153. The reversal of 51000125131 is 13152100015.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51000125131 is a prime.

It is a super-2 number, since 2×510001251312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51000125099 and 51000125108.

It is not an unprimeable number, because it can be changed into a prime (51000125531) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4168071 + ... + 4180288.

It is an arithmetic number, because the mean of its divisors is an integer number (6574333500).

Almost surely, 251000125131 is an apocalyptic number.

51000125131 is a deficient number, since it is larger than the sum of its proper divisors (1594542869).

51000125131 is a wasteful number, since it uses less digits than its factorization.

51000125131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8348549.

The product of its (nonzero) digits is 150, while the sum is 19.

Adding to 51000125131 its reverse (13152100015), we get a palindrome (64152225146).

The spelling of 51000125131 in words is "fifty-one billion, one hundred twenty-five thousand, one hundred thirty-one".

Divisors: 1 41 149 6109 8348359 342282719 1243905491 51000125131