Base | Representation |
---|---|
bin | 10111001100010101100001… |
… | …11111001010110110101011 |
3 | 20200120200120000200001021021 |
4 | 23212022300333022312223 |
5 | 23141101342210203001 |
6 | 300245420314553311 |
7 | 13512505336600504 |
oct | 1346126077126653 |
9 | 220520500601237 |
10 | 51001411022251 |
11 | 15283638a10978 |
12 | 58784b9438837 |
13 | 225c549129211 |
14 | c846a51d1bab |
15 | 5d69e51e6ba1 |
hex | 2e62b0fcadab |
51001411022251 has 2 divisors, whose sum is σ = 51001411022252. Its totient is φ = 51001411022250.
The previous prime is 51001411022153. The next prime is 51001411022273. The reversal of 51001411022251 is 15222011410015.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51001411022251 - 27 = 51001411022123 is a prime.
It is a super-2 number, since 2×510014110222512 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51001411029251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25500705511125 + 25500705511126.
It is an arithmetic number, because the mean of its divisors is an integer number (25500705511126).
Almost surely, 251001411022251 is an apocalyptic number.
51001411022251 is a deficient number, since it is larger than the sum of its proper divisors (1).
51001411022251 is an equidigital number, since it uses as much as digits as its factorization.
51001411022251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 800, while the sum is 25.
Adding to 51001411022251 its reverse (15222011410015), we get a palindrome (66223422432266).
The spelling of 51001411022251 in words is "fifty-one trillion, one billion, four hundred eleven million, twenty-two thousand, two hundred fifty-one".
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