Base | Representation |
---|---|
bin | 100101000111000000110… |
… | …1001010010110110010001 |
3 | 200001120202202122101100210 |
4 | 1022032001221102312101 |
5 | 1132030404111010241 |
6 | 14503013540434333 |
7 | 1034325135313122 |
oct | 112160151226621 |
9 | 20046682571323 |
10 | 5100301266321 |
11 | 1697031111498 |
12 | 6a45806a89a9 |
13 | 2acc58125cb1 |
14 | 138bda82a049 |
15 | 8ca0d11a316 |
hex | 4a381a52d91 |
5100301266321 has 16 divisors (see below), whose sum is σ = 6831265548800. Its totient is φ = 3384770561280.
The previous prime is 5100301266227. The next prime is 5100301266323. The reversal of 5100301266321 is 1236621030015.
It is not a de Polignac number, because 5100301266321 - 217 = 5100301135249 is a prime.
It is a super-3 number, since 3×51003012663213 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5100301266323) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12809955 + ... + 13202103.
It is an arithmetic number, because the mean of its divisors is an integer number (426954096800).
Almost surely, 25100301266321 is an apocalyptic number.
It is an amenable number.
5100301266321 is a deficient number, since it is larger than the sum of its proper divisors (1730964282479).
5100301266321 is a wasteful number, since it uses less digits than its factorization.
5100301266321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 411816.
The product of its (nonzero) digits is 6480, while the sum is 30.
Adding to 5100301266321 its reverse (1236621030015), we get a palindrome (6336922296336).
The spelling of 5100301266321 in words is "five trillion, one hundred billion, three hundred one million, two hundred sixty-six thousand, three hundred twenty-one".
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