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510050000497 is a prime number
BaseRepresentation
bin1110110110000010101…
…10010101111001110001
31210202112021001122011011
413123001112111321301
531324040300003442
61030151433350521
751564341320342
oct7330126257161
91722467048134
10510050000497
11187346a23634
1282a26868441
13391362c392b
141a987c800c9
15d4030bb117
hex76c1595e71

510050000497 has 2 divisors, whose sum is σ = 510050000498. Its totient is φ = 510050000496.

The previous prime is 510050000491. The next prime is 510050000521. The reversal of 510050000497 is 794000050015.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 371281830241 + 138768170256 = 609329^2 + 372516^2 .

It is a cyclic number.

It is not a de Polignac number, because 510050000497 - 23 = 510050000489 is a prime.

It is not a weakly prime, because it can be changed into another prime (510050000491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255025000248 + 255025000249.

It is an arithmetic number, because the mean of its divisors is an integer number (255025000249).

Almost surely, 2510050000497 is an apocalyptic number.

It is an amenable number.

510050000497 is a deficient number, since it is larger than the sum of its proper divisors (1).

510050000497 is an equidigital number, since it uses as much as digits as its factorization.

510050000497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6300, while the sum is 31.

The spelling of 510050000497 in words is "five hundred ten billion, fifty million, four hundred ninety-seven", and thus it is an aban number.