Base | Representation |
---|---|
bin | 100101000111000111000… |
… | …0110111000010001001001 |
3 | 200001121022100001212000001 |
4 | 1022032032012320101021 |
5 | 1132031321122121421 |
6 | 14503050410043001 |
7 | 1034333254424551 |
oct | 112161606702111 |
9 | 20047270055001 |
10 | 5100510348361 |
11 | 169712913796a |
12 | 6a461a719461 |
13 | 2acc8c54008c |
14 | 138c1a4d4161 |
15 | 8ca2166a691 |
hex | 4a38e1b8449 |
5100510348361 has 2 divisors, whose sum is σ = 5100510348362. Its totient is φ = 5100510348360.
The previous prime is 5100510348337. The next prime is 5100510348371. The reversal of 5100510348361 is 1638430150015.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5069504421136 + 31005927225 = 2251556^2 + 176085^2 .
It is a cyclic number.
It is not a de Polignac number, because 5100510348361 - 217 = 5100510217289 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5100510348361.
It is not a weakly prime, because it can be changed into another prime (5100510348371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2550255174180 + 2550255174181.
It is an arithmetic number, because the mean of its divisors is an integer number (2550255174181).
Almost surely, 25100510348361 is an apocalyptic number.
It is an amenable number.
5100510348361 is a deficient number, since it is larger than the sum of its proper divisors (1).
5100510348361 is an equidigital number, since it uses as much as digits as its factorization.
5100510348361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 37.
Adding to 5100510348361 its reverse (1638430150015), we get a palindrome (6738940498376).
The spelling of 5100510348361 in words is "five trillion, one hundred billion, five hundred ten million, three hundred forty-eight thousand, three hundred sixty-one".
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