Base | Representation |
---|---|
bin | 10111001100100111100101… |
… | …10110110010010110110011 |
3 | 20200121121120200120202210121 |
4 | 23212103302312302112303 |
5 | 23141231221122234403 |
6 | 300254102325111111 |
7 | 13513300522166041 |
oct | 1346236266622663 |
9 | 220547520522717 |
10 | 51011106055603 |
11 | 15287763569a31 |
12 | 587a364258497 |
13 | 226043289a045 |
14 | c84d44a4b391 |
15 | 5d6db14143bd |
hex | 2e64f2db25b3 |
51011106055603 has 2 divisors, whose sum is σ = 51011106055604. Its totient is φ = 51011106055602.
The previous prime is 51011106055573. The next prime is 51011106055607. The reversal of 51011106055603 is 30655060111015.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51011106055603 - 225 = 51011072501171 is a prime.
It is not a weakly prime, because it can be changed into another prime (51011106055607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25505553027801 + 25505553027802.
It is an arithmetic number, because the mean of its divisors is an integer number (25505553027802).
Almost surely, 251011106055603 is an apocalyptic number.
51011106055603 is a deficient number, since it is larger than the sum of its proper divisors (1).
51011106055603 is an equidigital number, since it uses as much as digits as its factorization.
51011106055603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 34.
Adding to 51011106055603 its reverse (30655060111015), we get a palindrome (81666166166618).
The spelling of 51011106055603 in words is "fifty-one trillion, eleven billion, one hundred six million, fifty-five thousand, six hundred three".
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