Search a number
-
+
51011313 = 317003771
BaseRepresentation
bin1100001010010…
…1111011110001
310112222122100220
43002211323301
5101024330223
65021203253
71156406013
oct302457361
9115878326
1051011313
1126881611
1215100529
13a750812
146abc1b3
1547296e3
hex30a5ef1

51011313 has 4 divisors (see below), whose sum is σ = 68015088. Its totient is φ = 34007540.

The previous prime is 51011293. The next prime is 51011347. The reversal of 51011313 is 31311015.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51011313 - 28 = 51011057 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51011292 and 51011301.

It is not an unprimeable number, because it can be changed into a prime (51011383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8501883 + ... + 8501888.

It is an arithmetic number, because the mean of its divisors is an integer number (17003772).

Almost surely, 251011313 is an apocalyptic number.

It is an amenable number.

51011313 is a deficient number, since it is larger than the sum of its proper divisors (17003775).

51011313 is a wasteful number, since it uses less digits than its factorization.

51011313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17003774.

The product of its (nonzero) digits is 45, while the sum is 15.

The square root of 51011313 is about 7142.2204530524. The cubic root of 51011313 is about 370.8703954654.

Adding to 51011313 its reverse (31311015), we get a palindrome (82322328).

The spelling of 51011313 in words is "fifty-one million, eleven thousand, three hundred thirteen".

Divisors: 1 3 17003771 51011313