Base | Representation |
---|---|
bin | 10111001100101011001011… |
… | …10010100111111011000011 |
3 | 20200121210120001222222101020 |
4 | 23212111211302213323003 |
5 | 23141244143243003011 |
6 | 300255021531040523 |
7 | 13513366355315346 |
oct | 1346254562477303 |
9 | 220553501888336 |
10 | 51013034344131 |
11 | 15288562a86712 |
12 | 587a801ba0143 |
13 | 226067c226882 |
14 | c85088b9a45d |
15 | 5d6e7585e006 |
hex | 2e6565ca7ec3 |
51013034344131 has 16 divisors (see below), whose sum is σ = 68174217344640. Its totient is φ = 33930346190400.
The previous prime is 51013034344081. The next prime is 51013034344169. The reversal of 51013034344131 is 13144343031015.
It is not a de Polignac number, because 51013034344131 - 215 = 51013034311363 is a prime.
It is a super-2 number, since 2×510130343441312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51013034344092 and 51013034344101.
It is not an unprimeable number, because it can be changed into a prime (51013034334131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6771610 + ... + 12160623.
It is an arithmetic number, because the mean of its divisors is an integer number (4260888584040).
Almost surely, 251013034344131 is an apocalyptic number.
51013034344131 is a deficient number, since it is larger than the sum of its proper divisors (17161183000509).
51013034344131 is a wasteful number, since it uses less digits than its factorization.
51013034344131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18934306.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 51013034344131 its reverse (13144343031015), we get a palindrome (64157377375146).
The spelling of 51013034344131 in words is "fifty-one trillion, thirteen billion, thirty-four million, three hundred forty-four thousand, one hundred thirty-one".
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