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51021420001 is a prime number
BaseRepresentation
bin101111100001000111…
…010001010111100001
311212200202210200110021
4233201013101113201
51313442440420001
635234450033441
73454233625426
oct574107212741
9155622720407
1051021420001
111a702297012
129a7ab78881
134a71569766
142680255d4d
1514d93a7ba1
hexbe11d15e1

51021420001 has 2 divisors, whose sum is σ = 51021420002. Its totient is φ = 51021420000.

The previous prime is 51021419971. The next prime is 51021420041. The reversal of 51021420001 is 10002412015.

51021420001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 36941224401 + 14080195600 = 192201^2 + 118660^2 .

It is a cyclic number.

It is not a de Polignac number, because 51021420001 - 219 = 51020895713 is a prime.

It is not a weakly prime, because it can be changed into another prime (51021420041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25510710000 + 25510710001.

It is an arithmetic number, because the mean of its divisors is an integer number (25510710001).

Almost surely, 251021420001 is an apocalyptic number.

It is an amenable number.

51021420001 is a deficient number, since it is larger than the sum of its proper divisors (1).

51021420001 is an equidigital number, since it uses as much as digits as its factorization.

51021420001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 16.

Adding to 51021420001 its reverse (10002412015), we get a palindrome (61023832016).

The spelling of 51021420001 in words is "fifty-one billion, twenty-one million, four hundred twenty thousand, one".