5103000433 has 4 divisors (see below), whose sum is σ = 5112758128. Its totient is φ = 5093242740.

The previous prime is 5103000403. The next prime is 5103000437. The reversal of 5103000433 is 3340003015.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5103000433 - 2⁵ = 5103000401 is a prime.

It is a super-2 number, since 2×5103000433² = 52081226838396374978, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5103000433.

It is not an unprimeable number, because it can be changed into a prime (5103000437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4878063 + ... + 4879108.

It is an arithmetic number, because the mean of its divisors is an integer number (1278189532).

Almost surely, 2^5103000433 is an apocalyptic number.

It is an amenable number.

5103000433 is a deficient number, since it is larger than the sum of its proper divisors (9757695).

5103000433 is an equidigital number, since it uses as much as digits as its factorization.

5103000433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9757694.

The product of its (nonzero) digits is 540, while the sum is 19.

The square root of 5103000433 is about 71435.2884294590. The cubic root of 5103000433 is about 1721.6381131900.

Adding to 5103000433 its reverse (3340003015), we get a palindrome (8443003448).

The spelling of 5103000433 in words is "five billion, one hundred three million, four hundred thirty-three", and thus it is an aban number.