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51031445041 is a prime number
BaseRepresentation
bin101111100001101101…
…100000111000110001
311212201110200000020001
4233201231200320301
51314003022220131
635235444550001
73454415061103
oct574155407061
9155643600201
1051031445041
111a707a13a75
129a823b2301
134a73669835
142681705573
1514da1d8261
hexbe1b60e31

51031445041 has 2 divisors, whose sum is σ = 51031445042. Its totient is φ = 51031445040.

The previous prime is 51031445033. The next prime is 51031445137. The reversal of 51031445041 is 14054413015.

51031445041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 34260159025 + 16771286016 = 185095^2 + 129504^2 .

It is a cyclic number.

It is not a de Polignac number, because 51031445041 - 23 = 51031445033 is a prime.

It is not a weakly prime, because it can be changed into another prime (51031445011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25515722520 + 25515722521.

It is an arithmetic number, because the mean of its divisors is an integer number (25515722521).

Almost surely, 251031445041 is an apocalyptic number.

It is an amenable number.

51031445041 is a deficient number, since it is larger than the sum of its proper divisors (1).

51031445041 is an equidigital number, since it uses as much as digits as its factorization.

51031445041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 51031445041 its reverse (14054413015), we get a palindrome (65085858056).

The spelling of 51031445041 in words is "fifty-one billion, thirty-one million, four hundred forty-five thousand, forty-one".