Base | Representation |
---|---|
bin | 10111001101010001010111… |
… | …01011011110111101001011 |
3 | 20200200202110202011002121021 |
4 | 23212220223223132331023 |
5 | 23142113134230332342 |
6 | 300312252034453311 |
7 | 13515023360423434 |
oct | 1346505353367513 |
9 | 220622422132537 |
10 | 51033534230347 |
11 | 152962226a4639 |
12 | 5882783434237 |
13 | 2262598346866 |
14 | c8607160848b |
15 | 5d777541e567 |
hex | 2e6a2badef4b |
51033534230347 has 2 divisors, whose sum is σ = 51033534230348. Its totient is φ = 51033534230346.
The previous prime is 51033534230281. The next prime is 51033534230401. The reversal of 51033534230347 is 74303243533015.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51033534230347 - 215 = 51033534197579 is a prime.
It is not a weakly prime, because it can be changed into another prime (51033534230747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25516767115173 + 25516767115174.
It is an arithmetic number, because the mean of its divisors is an integer number (25516767115174).
Almost surely, 251033534230347 is an apocalyptic number.
51033534230347 is a deficient number, since it is larger than the sum of its proper divisors (1).
51033534230347 is an equidigital number, since it uses as much as digits as its factorization.
51033534230347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1360800, while the sum is 43.
The spelling of 51033534230347 in words is "fifty-one trillion, thirty-three billion, five hundred thirty-four million, two hundred thirty thousand, three hundred forty-seven".
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