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510398113 is a prime number
BaseRepresentation
bin11110011011000…
…000111010100001
31022120101220120211
4132123000322201
52021130214423
6122351334121
715435212101
oct3633007241
91276356524
10510398113
11242119725
12122b21341
1381985c24
144bb01201
152ec1e10d
hex1e6c0ea1

510398113 has 2 divisors, whose sum is σ = 510398114. Its totient is φ = 510398112.

The previous prime is 510398107. The next prime is 510398149. The reversal of 510398113 is 311893015.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 494261824 + 16136289 = 22232^2 + 4017^2 .

It is a cyclic number.

It is not a de Polignac number, because 510398113 - 25 = 510398081 is a prime.

It is not a weakly prime, because it can be changed into another prime (510398153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255199056 + 255199057.

It is an arithmetic number, because the mean of its divisors is an integer number (255199057).

Almost surely, 2510398113 is an apocalyptic number.

It is an amenable number.

510398113 is a deficient number, since it is larger than the sum of its proper divisors (1).

510398113 is an equidigital number, since it uses as much as digits as its factorization.

510398113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3240, while the sum is 31.

The square root of 510398113 is about 22591.9922317621. The cubic root of 510398113 is about 799.1648122343.

The spelling of 510398113 in words is "five hundred ten million, three hundred ninety-eight thousand, one hundred thirteen".