5104013001 has 8 divisors (see below), whose sum is σ = 6809933184. Its totient is φ = 3400384080.

The previous prime is 5104012993. The next prime is 5104013107. The reversal of 5104013001 is 1003104015.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5104013001 - 2³ = 5104012993 is a prime.

It is not an unprimeable number, because it can be changed into a prime (5104013701) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 567610 + ... + 576531.

It is an arithmetic number, because the mean of its divisors is an integer number (851241648).

Almost surely, 2^5104013001 is an apocalyptic number.

It is an amenable number.

5104013001 is a deficient number, since it is larger than the sum of its proper divisors (1705920183).

5104013001 is a wasteful number, since it uses less digits than its factorization.

5104013001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1145631.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 5104013001 is about 71442.3753874408. The cubic root of 5104013001 is about 1721.7519782512.

Adding to 5104013001 its reverse (1003104015), we get a palindrome (6107117016).

The spelling of 5104013001 in words is "five billion, one hundred four million, thirteen thousand, one".