Base | Representation |
---|---|
bin | 100101001000111000101… |
… | …0011010001001001101100 |
3 | 200001222010222102001001111 |
4 | 1022101301103101021230 |
5 | 1132112122414232134 |
6 | 14504520531321404 |
7 | 1034526600222625 |
oct | 112216123211154 |
9 | 20058128361044 |
10 | 5104322024044 |
11 | 1698804793261 |
12 | 6a5303150264 |
13 | 2b0449134989 |
14 | 13909c824a4c |
15 | 8cb960e0c64 |
hex | 4a4714d126c |
5104322024044 has 12 divisors (see below), whose sum is σ = 8932651026264. Its totient is φ = 2552136016544.
The previous prime is 5104322024027. The next prime is 5104322024047. The reversal of 5104322024044 is 4404202234015.
It is a super-3 number, since 3×51043220240443 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 5104322023997 and 5104322024015.
It is not an unprimeable number, because it can be changed into a prime (5104322024047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5785582 + ... + 6609205.
It is an arithmetic number, because the mean of its divisors is an integer number (744387585522).
Almost surely, 25104322024044 is an apocalyptic number.
It is an amenable number.
5104322024044 is a deficient number, since it is larger than the sum of its proper divisors (3828329002220).
5104322024044 is a wasteful number, since it uses less digits than its factorization.
5104322024044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12497744 (or 12497742 counting only the distinct ones).
The product of its (nonzero) digits is 30720, while the sum is 31.
Adding to 5104322024044 its reverse (4404202234015), we get a palindrome (9508524258059).
The spelling of 5104322024044 in words is "five trillion, one hundred four billion, three hundred twenty-two million, twenty-four thousand, forty-four".
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