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5104330401 = 31701443467
BaseRepresentation
bin1001100000011110…
…11110011010100001
3111011201200211222010
410300033132122201
540423202033101
62202255303133
7240330043512
oct46017363241
914151624863
105104330401
11218a296a85
12ba551aaa9
1363465a461
14365c9ca09
151ed1b42d6
hex1303de6a1

5104330401 has 4 divisors (see below), whose sum is σ = 6805773872. Its totient is φ = 3402886932.

The previous prime is 5104330391. The next prime is 5104330417. The reversal of 5104330401 is 1040334015.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5104330401 - 25 = 5104330369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5104330471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 850721731 + ... + 850721736.

It is an arithmetic number, because the mean of its divisors is an integer number (1701443468).

Almost surely, 25104330401 is an apocalyptic number.

It is an amenable number.

5104330401 is a deficient number, since it is larger than the sum of its proper divisors (1701443471).

5104330401 is a wasteful number, since it uses less digits than its factorization.

5104330401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1701443470.

The product of its (nonzero) digits is 720, while the sum is 21.

The square root of 5104330401 is about 71444.5967236151. The cubic root of 5104330401 is about 1721.7876673420.

Adding to 5104330401 its reverse (1040334015), we get a palindrome (6144664416).

The spelling of 5104330401 in words is "five billion, one hundred four million, three hundred thirty thousand, four hundred one".

Divisors: 1 3 1701443467 5104330401