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51043350401 = 54793315083
BaseRepresentation
bin101111100010011010…
…111011011110000001
311212202022001212022022
4233202122323132001
51314014044203101
635240552051225
73454621214441
oct574232733601
9155668055268
1051043350401
111a71370570a
129a86393b15
134a75c77724
142683124121
1514db28aa1b
hexbe26bb781

51043350401 has 4 divisors (see below), whose sum is σ = 51136666032. Its totient is φ = 50950034772.

The previous prime is 51043350377. The next prime is 51043350409. The reversal of 51043350401 is 10405334015.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51043350401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51043350409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46656995 + ... + 46658088.

It is an arithmetic number, because the mean of its divisors is an integer number (12784166508).

Almost surely, 251043350401 is an apocalyptic number.

It is an amenable number.

51043350401 is a deficient number, since it is larger than the sum of its proper divisors (93315631).

51043350401 is an equidigital number, since it uses as much as digits as its factorization.

51043350401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93315630.

The product of its (nonzero) digits is 3600, while the sum is 26.

Adding to 51043350401 its reverse (10405334015), we get a palindrome (61448684416).

The spelling of 51043350401 in words is "fifty-one billion, forty-three million, three hundred fifty thousand, four hundred one".

Divisors: 1 547 93315083 51043350401