Base | Representation |
---|---|
bin | 101111100010011010… |
… | …111011011110000011 |
3 | 11212202022001212022101 |
4 | 233202122323132003 |
5 | 1314014044203103 |
6 | 35240552051231 |
7 | 3454621214443 |
oct | 574232733603 |
9 | 155668055271 |
10 | 51043350403 |
11 | 1a713705711 |
12 | 9a86393b17 |
13 | 4a75c77726 |
14 | 2683124123 |
15 | 14db28aa1d |
hex | be26bb783 |
51043350403 has 4 divisors (see below), whose sum is σ = 51054492528. Its totient is φ = 51032208280.
The previous prime is 51043350377. The next prime is 51043350409. The reversal of 51043350403 is 30405334015.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51043350403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51043350409) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5564188 + ... + 5573353.
It is an arithmetic number, because the mean of its divisors is an integer number (12763623132).
Almost surely, 251043350403 is an apocalyptic number.
51043350403 is a deficient number, since it is larger than the sum of its proper divisors (11142125).
51043350403 is a wasteful number, since it uses less digits than its factorization.
51043350403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11142124.
The product of its (nonzero) digits is 10800, while the sum is 28.
Adding to 51043350403 its reverse (30405334015), we get a palindrome (81448684418).
The spelling of 51043350403 in words is "fifty-one billion, forty-three million, three hundred fifty thousand, four hundred three".
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