Base | Representation |
---|---|
bin | 10111001101111010001110… |
… | …01110101100101011000011 |
3 | 20200202212002120120211101112 |
4 | 23212331013032230223003 |
5 | 23142443101122023013 |
6 | 300330320521553535 |
7 | 13516431113331014 |
oct | 1346750716545303 |
9 | 220685076524345 |
10 | 51055471282883 |
11 | 152a455a586921 |
12 | 5886a860458ab |
13 | 2264683129112 |
14 | c87152c8100b |
15 | 5d810b266ba8 |
hex | 2e6f473acac3 |
51055471282883 has 2 divisors, whose sum is σ = 51055471282884. Its totient is φ = 51055471282882.
The previous prime is 51055471282867. The next prime is 51055471282913. The reversal of 51055471282883 is 38828217455015.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51055471282883 - 24 = 51055471282867 is a prime.
It is a super-2 number, since 2×510554712828832 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51055471285883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25527735641441 + 25527735641442.
It is an arithmetic number, because the mean of its divisors is an integer number (25527735641442).
Almost surely, 251055471282883 is an apocalyptic number.
51055471282883 is a deficient number, since it is larger than the sum of its proper divisors (1).
51055471282883 is an equidigital number, since it uses as much as digits as its factorization.
51055471282883 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504000, while the sum is 59.
The spelling of 51055471282883 in words is "fifty-one trillion, fifty-five billion, four hundred seventy-one million, two hundred eighty-two thousand, eight hundred eighty-three".
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