Base | Representation |
---|---|
bin | 10111001110010111010011… |
… | …11111001010111011010001 |
3 | 20200211100101211221022122022 |
4 | 23213023221333022323101 |
5 | 23143222041210104333 |
6 | 300341422224421225 |
7 | 13520523066126506 |
oct | 1347135177127321 |
9 | 220740354838568 |
10 | 51071086800593 |
11 | 15300143095462 |
12 | 5889b03777815 |
13 | 2265ca1344c22 |
14 | c87bd4b2b4ad |
15 | 5d8722111c98 |
hex | 2e72e9fcaed1 |
51071086800593 has 2 divisors, whose sum is σ = 51071086800594. Its totient is φ = 51071086800592.
The previous prime is 51071086800571. The next prime is 51071086800683. The reversal of 51071086800593 is 39500868017015.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 27304564792129 + 23766522008464 = 5225377^2 + 4875092^2 .
It is a cyclic number.
It is not a de Polignac number, because 51071086800593 - 212 = 51071086796497 is a prime.
It is not a weakly prime, because it can be changed into another prime (51071086800523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25535543400296 + 25535543400297.
It is an arithmetic number, because the mean of its divisors is an integer number (25535543400297).
Almost surely, 251071086800593 is an apocalyptic number.
It is an amenable number.
51071086800593 is a deficient number, since it is larger than the sum of its proper divisors (1).
51071086800593 is an equidigital number, since it uses as much as digits as its factorization.
51071086800593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1814400, while the sum is 53.
The spelling of 51071086800593 in words is "fifty-one trillion, seventy-one billion, eighty-six million, eight hundred thousand, five hundred ninety-three".
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