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51083656673513 = 311164256130783
BaseRepresentation
bin10111001110101110101110…
…01101011011100011101001
320200212112211212101000200012
423213113113031123203221
523143423312102023023
6300351301412421305
713521446430234362
oct1347272715334351
9220775755330605
1051083656673513
1115305503497a92
125890431317835
132267225587559
14c886682ccb69
155d8c0a8ed978
hex2e75d735b8e9

51083656673513 has 4 divisors (see below), whose sum is σ = 51247912804608. Its totient is φ = 50919400542420.

The previous prime is 51083656673503. The next prime is 51083656673561. The reversal of 51083656673513 is 31537665638015.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51083656673513 is a prime.

It is a super-2 number, since 2×510836566735132 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51083656673503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82128065081 + ... + 82128065702.

It is an arithmetic number, because the mean of its divisors is an integer number (12811978201152).

Almost surely, 251083656673513 is an apocalyptic number.

It is an amenable number.

51083656673513 is a deficient number, since it is larger than the sum of its proper divisors (164256131095).

51083656673513 is a wasteful number, since it uses less digits than its factorization.

51083656673513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 164256131094.

The product of its (nonzero) digits is 40824000, while the sum is 59.

The spelling of 51083656673513 in words is "fifty-one trillion, eighty-three billion, six hundred fifty-six million, six hundred seventy-three thousand, five hundred thirteen".

Divisors: 1 311 164256130783 51083656673513